how to wire up 2 plug pickup sensor (speed)

[Wildsupra]

Im running a jzx90 auto box and wish to use the 2 pin plug sensor as a speed sensor when combined with my aftermarket gearbox controller.
The sensor is a 4 tooth pressumably a magnetic pickup type??

It has 2 wires going to it, how do these work? is 1 wire 12v in and the other a output? or does it generate its own voltage somehow? Im really confused.....

How do i wire it to submit some sort of output signal?
My tranny controller has all kinds of setting i can adjust depending on wot voltage or signwave or woteva this thing is going to create, i just need to figure out how to wire or power it up.

Cheers
Matty

[Mos]

It's a reluctor type pickup.

The sensor is a coil with a magnet. When the rotor lobe moves past the sensor it affects the magnetic field provided by the magnet. This change in magnetic field induces a voltage on the coil.

The voltage (provided polarity is correct) will rise to a peak, then fall/drop/swing past zero to the negative peak, and then return to zero. The drop past zero is called the zero crossing on the falling edge and is the point which most circuits recognise as it is highly immune to noise.

Normally one end of the sensor (usually the negative) will be grounded internally in the ECU.

I would assume your controller would have an appropriate input for this type of signal (I don't know much about the aftermarket tranny controllers).

Mos.

[FASTFOO]

It should make less than 1 volt and be signwave.
you will allso find it is most likly 20 pulse per tail shaft rev.

MATT.

[Wildsupra]

Cheers guys, its a 4 pulse per rev, so mos should i be wiring one wire to ground and using the other wire as the output signal wire, which in turn is connected to the input signal wire for the speedo signal on the tranny controller?

Is there any way to tell which should be earth and which is signal? and will i blow it if i get itwrong the first time?

Cheers
Matty